HVAC Formula Calculi

_20220628084907

I. Temperature.

Celsius (C) and Fahrenheit (F) ;

Fahrenheit = 32 + Celsius × 1.8

Celsius = (Fahrenheit -32) /1.8

Kelvin (K) and Celsius (C).

Kelvin (K) = Celsius (C) +273.15

II, Pressura conversionem

Mpa、Kpa、pa、bar

1Mpa=1000Kpa;

1Kpa=1000pa;

1Mpa=10bar;

1bar=0.1Mpa=100Kpa;

1atmospher=101.325Kpa=1bar=1Kilogram;

1bar=14.5psi;

1psi=6.895Kpa;

1 kg/cm2=105=10 mH2O=1 bar=0.1 MPa

1 Pa=0.1 mmH2O=0.0001 mH2O

1 mH2O=104 Pa=10 kPa

III

1CFM = 1.699 M³/H=0.4719 l/s

1M³/H=0.5886CFM

1l/s=2.119CFM

1FPM=0.3048 m/min=0.00508 m/s

IV-Cooling facultatem ac potestatem.

1KW=1000 W

1KW=861Kcal/h=0.39 P. refrigerandi facultatem)

1W= 1 J/s

1USTR=3024Kcal/h=3517W( refrigerandi facultatem)

1BTU=0.252kcal/h=1055J

1BTU/H=0.252kcal/h

1BTU/H=0.2931W( refrigerandi facultatem)

1MTU/H=0.2931KW( refrigerandi facultatem)

1HP(electricity)=0.75KW(electricity)

1KW(electricity)=1.34HP(electricity)

1RT (referendi facultatem) = 3.517KW( refrigerandi facultatem)

1KW, refrigerandi facultatem.= 3.412MBH

1P, refrigerandi facultatem.=200kcal/h=2.56KW

1kcal/h=1.163W

V、Caeli condicionescrassitudine institutionem et facultatem refrigerandi

1.5mm2=12A-20A(2650~4500W) 1P~2P

2.5mm2=20-25A(4500~5500W) 2P

4mm2=25-32A(5500~7500W) 2P~3P

6mm2=32-40A(7500~8500W) 3P~4P

VI.

1、Selectio expansion valvae, frigus ton + 1.25% annonas

2、Press power: 1P = 0.735kW

3、 Refrigerant crimen: facultatem refrigerandi (KW) ÷3.516 x 0.58

4、 Aquae fluxus aeris frigidior: capacitas refrigerandi (KW) differentia temperatus 1.163

5、 Refrigerationis aqua fluit rate of aqua refrigeratum machina cochleæ: facultatem refrigerandi (KW) -0.86÷ differentia temperatus

VI Aqua refrigerium rate of aqua refrigeratum machina cochlea:(refrigerandi capacitatemKW+ press potentia) 0.86÷ differentia temperatus

7、Gross calefactio pretii QT=QS+QL

8、Air refrigeratioQT = 0.24*∝*L*(h1-h2)

9、Significat calorem aeris refrigerationem:QS=Cp*∝*L*(T1-T2)

10、Latent calor aeris refrigeratio:QL=600*∝*L*(W1-W2)

11、Aquae congelatiomagnitudo.L/sV1= Q1/(4.187△T1)

12、 Aquae refrigerationis volumen:L/sV2=Q2/(4.187△T2)=(3.516+KW/TR)TR,Q2=Q1+N=TR*3.516+KW/TR*TR=(3.516+KW/TR) *TR

13、 Refrigeratio efficientiae: EER = refrigeratio capacitatis (Mbtu/h)/ potentia consummatio (KW);COP= Refrigeratio capacitatis (KW) / potentia consummatio (KW)

14、 NPLV=1/(0.01/A+0.42/B+0.45/C+0.12/D)

15、Plene onus current (tres tempus) :FLA=N/√3 UCOSφ

16、Fresh air volume:Lo = nV

17Aircopia volume:L=Qs/〔Cp*∝*(T1-T2)〕

18、Potentia fan:N1=L1*H1/(102*n1*n2)

19、Potentia aquae pump:N2 = L2*H2*r/(102*n3*n4)

20、 fistula diameter:D=√4*1000L2/(π*v)

21、Duct area:F=a*b*L1/(1000u)


Post tempus: Iun-28-2022