I. Temperature.
Celsius (C) and Fahrenheit (F) ;
Fahrenheit = 32 + Celsius × 1.8
Celsius = (Fahrenheit -32) /1.8
Kelvin (K) and Celsius (C).
Kelvin (K) = Celsius (C) +273.15
II, Pressura conversionem
Mpa、Kpa、pa、bar
1Mpa=1000Kpa;
1Kpa=1000pa;
1Mpa=10bar;
1bar=0.1Mpa=100Kpa;
1atmospher=101.325Kpa=1bar=1Kilogram;
1bar=14.5psi;
1psi=6.895Kpa;
1 kg/cm2=105=10 mH2O=1 bar=0.1 MPa
1 Pa=0.1 mmH2O=0.0001 mH2O
1 mH2O=104 Pa=10 kPa
III
1CFM = 1.699 M³/H=0.4719 l/s
1M³/H=0.5886CFM
1l/s=2.119CFM
1FPM=0.3048 m/min=0.00508 m/s
IV-Cooling facultatem ac potestatem.
1KW=1000 W
1KW=861Kcal/h=0.39 P. refrigerandi facultatem)
1W= 1 J/s
1USTR=3024Kcal/h=3517W( refrigerandi facultatem)
1BTU=0.252kcal/h=1055J
1BTU/H=0.252kcal/h
1BTU/H=0.2931W( refrigerandi facultatem)
1MTU/H=0.2931KW( refrigerandi facultatem)
1HP(electricity)=0.75KW(electricity)
1KW(electricity)=1.34HP(electricity)
1RT (referendi facultatem) = 3.517KW( refrigerandi facultatem)
1KW, refrigerandi facultatem.= 3.412MBH
1P, refrigerandi facultatem.=200kcal/h=2.56KW
1kcal/h=1.163W
V、Caeli condicionescrassitudine institutionem et facultatem refrigerandi
1.5mm2=12A-20A(2650~4500W) 1P~2P
2.5mm2=20-25A(4500~5500W) 2P
4mm2=25-32A(5500~7500W) 2P~3P
6mm2=32-40A(7500~8500W) 3P~4P
VI.
1、Selectio expansion valvae, frigus ton + 1.25% annonas
2、Press power: 1P = 0.735kW
3、 Refrigerant crimen: facultatem refrigerandi (KW) ÷3.516 x 0.58
4、 Aquae fluxus aeris frigidior: capacitas refrigerandi (KW) differentia temperatus 1.163
5、 Refrigerationis aqua fluit rate of aqua refrigeratum machina cochleæ: facultatem refrigerandi (KW) -0.86÷ differentia temperatus
VI Aqua refrigerium rate of aqua refrigeratum machina cochlearefrigerandi capacitatemKW+ press potentia) 0.86÷ differentia temperatus
7、Gross calefactio pretii QT=QS+QL
8、Air refrigeratioQT = 0.24*∝*L*(h1-h2)
9、Significat calorem aeris refrigerationem:QS=Cp*∝*L*(T1-T2)
10、Latent calor aeris refrigeratio:QL=600*∝*L*(W1-W2)
11、Aquae congelatiomagnitudo.L/sV1= Q1/(4.187△T1)
12、 Aquae refrigerationis volumen:L/sV2=Q2/(4.187△T2)=(3.516+KW/TR)TR,Q2=Q1+N=TR*3.516+KW/TR*TR=(3.516+KW/TR) *TR
13、 Refrigeratio efficientiae: EER = refrigeratio capacitatis (Mbtu/h)/ potentia consummatio (KW);COP= Refrigeratio capacitatis (KW) / potentia consummatio (KW)
14、 NPLV=1/(0.01/A+0.42/B+0.45/C+0.12/D)
15、Plene onus current (tres tempus) :FLA=N/√3 UCOSφ
16、Fresh air volume:Lo = nV
17Aircopia volume:L=Qs/〔Cp*∝*(T1-T2)〕
18、Potentia fan:N1=L1*H1/(102*n1*n2)
19、Potentia aquae pump:N2 = L2*H2*r/(102*n3*n4)
20、 fistula diameter:D=√4*1000L2/(π*v)
21、Duct area:F=a*b*L1/(1000u)
Post tempus: Iun-28-2022